Problema Solution
A golf ball is launched upward with an initial speed of 30m/sec by a golfer on the third level of the golf club at Chelsea Piers Manhattan, which is 10m above ground. How high above the ground will the ball be after 3 sec.
Answer provided by our tutors
let
v0 = 30 m/s the initial speed
h0 = 10 m
t = 3 sec
g = 9.81 m/s^2
h = the height above the ground
h(t) =-(1/2)gt^2+v0t+h0
h(3) = -(1/2)9.81*3^2+ 30*3 +10
h(3) = 55.855 m
after 3 seconds the ball will be 55.855 m above the ground.