Problema Solution

You are designing a rectangular birthday card for a friend. You want the card’s length to be 1 inch more than twice the card’s width. The area of the card is 88 in2. What are the dimensions of the card?

Answer provided by our tutors

let


l = the length of the card, l>0

w = the width of the card, w>0


the card’s length to be 1 inch more than twice the card’s width


l = 2w + 1


the area of the card is 88 in2


l*w = 88


plug l = 2w + 1 into the last equation


(2w + 1)*w = 88


by soling we find:


w = 6.39 in


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l = 6.39 + 1 = 7.39 in


the dimensions of the card are 6.39 in and 7.39 in.