Problema Solution
If 1-cos y =0.2 and angle y us acute what is the value of tan(1/2)y?
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Answer provided by our tutors
1-cos y =0.2
cos y = 1 - 0.2
cos y = 0.8
we will use the formula:
(tan(1/2)y)^2 = (1 - cos y)/(1 + cos y)
(tan(1/2)y)^2 = 0.2/(1 + 0.8)
(tan(1/2)y)^2 = 0.2/1.8
tan(1/2)y = 1/9
tan(1/2)y = 0.11111