Problema Solution
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifreeze?
Answer provided by our tutors
let
x = gal of the 80% antifreeze solution
100 gal of the 10% antifreeze solution
x +100 = gal of the mix
0.80x + 0.10*100 = 0.70(x + 100)
by solving we find
x = 600 gal
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600 gallons of 80% antifreeze solution should be used for the mixture.