Problema Solution
The perimeter of the rectangular filed is 248 yards. The length of the filed is 2 yards less than double the width. what are the dimensions of the playing field?
Answer provided by our tutors
let
l = the length of the rectangular field
w = the width of the rectangular field
the perimeter of the rectangular filed is 248 yards
2(l + w) = 248 divide both sides by 2
l + w = 124
the length of the filed is 2 yards less than double the width
l = 2w - 2
by solving the system of equations
l + w = 124
l = 2w - 2
we find
l = 82 yd
w = 42 yd
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the dimensions of the playing field are 82 yd and 42 yd.