Problema Solution

a scientist needs 30 liters of a 60% solution. He has a 40% solution and a 70% solution. How many of each does he need to get 30 liters of a 60% solution?

Answer provided by our tutors

let


x = liters of the 40% solution

y = liters of the 70% solution


x + y = 30


0.40x + 0.70y = 0.60*30


by solving the above system of equations we find


x = 10 l


y = 20 l


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he needs to use 10 liters of the 60% solution and 20 liters of the 40% solution.