Problema Solution
How many liters of 10% alcohol solution must be mixed with 90 liters of 60% solution to get a 30% solution?
Answer provided by our tutors
let
x = L of 10% alcohol solution, x>0
10% alcohol solution mixed with 90 liters of 60% solution to get a 30% solution
0.10x + 0.60*90 = 0.30(x + 90)
by solving the equations we find
x = 135 L
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135 liters of 10% alcohol solution must be used for the mix.