Problema Solution
a motorboat travels 228 km in 6 hours going upstream. It travels 384 km going downstream in the same amount of time. what is the rate of the boat in still water and what is the rate of the current
Answer provided by our tutors
let
b = the rate of the boat in still water
c = the rate of the current
t = 6 hr the time of the travel in one direction
d1 = 338 km the distance of the trip upstream
d2 = 384 km the distance of the trip downstream
the rate of the boar traveling upstream is: b - c
the rate of the boar traveling downstream is: b + c
since the rate = distance/time => distance = time*rate
d1 = t(b - c)
d2 = t(b + c)
or we have the following system
6(b - c) = 338
6(b + c) = 384
by solving the system of equations we find
b = 60.17 km/hr
c = 3.83 km/hr
click here to see the step by step solution of the system of equations
the rate of the boat in still water is 60.17 km/hr and the rate of the current is 3.83 km/hr.