Problema Solution

P(t)= −16 (t) 2+339(t)ˏ how long before object hits the ground

Answer provided by our tutors

the object will hit the ground when P(t) = 0, for some t, and t > 0


P(t)= −16 (t)^2+339(t)


P(t)= 0


−16 (t)^2+339(t) = 0


by solving the quadratic equation we find


t = 339/16 s


t = 21.19 s


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the object will hit the ground after 21.19 seconds.