Problema Solution
A rectangle lot is surrounded by 70 meters of fencing on its perimeter. The length of the lot is 5 meters more than the width. Find the length and width of the lot.
Answer provided by our tutors
let
l = the length of the lot
w = the width of the lot
the perimeter is 70 meters
2(l + w) = 70 divide both sides by 2
l + w = 35
the length of the lot is 5 meters more than the width
l = 5 + w
by solving the system of equations
l + w = 35
l = 5 + w
we find
l = 20 m
w = 15 m
click here to see the step by step solution of the system of equations
the length of the lot is 20 meters.
the width of the lot is 15 meters.