Problema Solution

the length of a rectangle is 5in greater than the width. the area is 104in^2. find the lenght and the width

Answer provided by our tutors

let


l = the length of the rectangle, l>0

w = the width of the rectangle, w>0


the length of a rectangle is 5in greater than the width


l = 5 + w


the area is 104 in^2


l*w = 104


plug l = 5 + w into the last equations


(5 + w)w = 104


by solving we find


w = 8 in


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l = 5 + 8


l = 13 in


the length is 13 in and the width is 8 in.