Problema Solution
It takes 5 hours for a boat to go a distance of 15 miles against the current and 3 hours in the direction of the current. What is the speed of the boat in still water and what is the speed of the current?
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b = the rate of the boat in still water
c = the rate of the current
t1 = 5 hr the time of the travel against the current
t2 = 3 hr the time of the travel with the current
d = 15 mi the distance of the trip in one direction
the rate of the boar traveling upstream is: b - c
the rate of the boar traveling downstream is: b + c
since the rate = distance/time => distance = time*rate
d = t1(b - c)
t1(b - c) = d
5(b - c) = 15 divide both sides by 5
b - c = 3
d = t2(b + c)
t2(b + c) = d
3(b + c) = 15 divide both sides by 3
b + c = 5
we have the following system
b - c = 3
b + c = 5
by solving we find
b = 4 mph
c = 1 mph
click here to see the step by step solution of the system of equations
he speed of the boat in still water is 4 mph.
the speed of the current is 1 mph.
let
b = the rate of the boat in still water
c = the rate of the current
t1 = 5 hr the time of the travel against the current
t2 = 3 hr the time of the travel with the current
d = 15 mi the distance of the trip in one direction
the rate of the boar traveling upstream is: b - c
the rate of the boar traveling downstream is: b + c
since the rate = distance/time => distance = time*rate
d = t1(b - c)
t1(b - c) = d
5(b - c) = 15 divide both sides by 5
b - c = 3
d = t2(b + c)
t2(b + c) = d
3(b + c) = 15 divide both sides by 3
b + c = 5
we have the following system
b - c = 3
b + c = 5
by solving we find
b = 4 mph
c = 1 mph
click here to see the step by step solution of the system of equations
he speed of the boat in still water is 4 mph.
the speed of the current is 1 mph.