Problema Solution
By weight, alloy A is 70% copper and 30% zinc. Alloy B is 40% copper and 60% zinc. How much of each of these are required to make 300g of an alloy that is 60% copper and 40% zinc.
Answer provided by our tutors
let
a = grams of alloy A
b = grams of alloy B
0.70a + 0.40b = 0.60*700
0.30a + 0.60b = 0.50*700
by solving the above system of equations we find
a = 373.33 g
b = 396.67 g
click here to see the step by step solution of the equations
373.33 g of alloy A and 396.67 g of alloy B is required.
let
a = grams of alloy A
b = grams of alloy B
0.70a + 0.40b = 0.60*700
0.30a + 0.60b = 0.40*700
by solving the above system of equations we find
a = 466.67 g
b = 233.33 g
click here to see the step by step solution of the equations
466.67 g of alloy A and 233.33 g of alloy B is required.
let
a = grams of alloy A
b = grams of alloy B
0.70a + 0.40b = 0.60*700
0.30a + 0.60b = 0.40*700
by solving the above system of equations we find
a = 466.67 g
b = 233.33 g
click here to see the step by step solution of the equations
466.67 g of alloy A and 233.33 g of alloy B is required.