Problema Solution
The perimeter of a rectangular field is 320 yd. The length is 60 yd longer than the width. Find dimensions
The Smaller of two sides is what yards.
Answer provided by our tutors
let
l = the length of the field
w = the width of the field
the perimeter of a rectangular field is 320 yd
2(l + w) = 320 divide both sides by 2
l + w = 160
the length is 60 yd longer than the width
l = w + 60
by solving the system of equations
l + w = 160
l = w + 60
we find
l = 110 yd
w = 50 yd
click here to see the step by step solution of the system of equations
the dimensions of the yard are: the length is 110 yd and the width is 50 yd.
the smaller of the two sides is 50 yd.