Problema Solution
Two trains leave towns 1428km apart at the same time and travel toward each other. One train travels 22km/h slower than the other. If they meet in 6 hours, what is the rate of each train?
Answer provided by our tutors
let
x = the rate of the first train
y = the rate of the second train
t = 6 hr the time of the travel before meeting
one train travels 22 km/h slower than the other:
y = x + 22
since rate = distance/time => distance = time*rate
x*t + y*t = 1428
6(x + y) = 1428 divide both sides by 6
x + y = 238
plug y = x + 22 into the last equation
x + x + 22 = 238
by solving we find
x = 108 km/h
click here to see the step by step solution of the equation
y = x + 22
y = 108 + 22
y = 130 km/h
the rate of the faster train is 130 km/h.
the rate of the slower train is 108 km/h.