Problema Solution
The length of a rectangle is twice it's width. If the perimeter is 64 meters, find the dimensions of the rectangle
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
the length of a rectangle is twice it's width
l = 2w
the perimeter is 64 meters
2(l + w) = 64 divide both sides by 2
l + w = 32
by solving the system of equations
l = 2w
l + w = 32
we find
l = 21.33 m
w = 10.67 m
click here to see the step by step solution of the system of equations
the length of the rectangle is 21.33 meters.
the width of the rectangle is 10.67 meters.