Problema Solution

The length of a rectangle is four times it's width. If the perimeter of the rectangle is 90ft, find it's area

Answer provided by our tutors

let


l = the length of the rectangle

w = the width of the rectangle

P = 90 ft the perimeter of the rectangle

A = the area


the length of a rectangle is four times it's width


l = 4w


the perimeter of the rectangle is 90 ft


2(l + w) = 90 divide both sided by 2


l + w = 45


by solving the system of equations


l = 4w

l + w = 45


we find


l = 36 ft


w = 9 ft


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A = l*w


A = 36*9


A = 324 ft^2


the area of the rectangle is 324 ft^2.