Problema Solution
The length of a rectangle 7yd is more than twice the width, and the area of the rectangle is 99yd^2 . Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the area of a rectangle is 99 yd^2
l*w = 54
the length of the rectangle is 7 yds more than twice the width
l = 7 + 2w
plug l = 7 + 2w into l*w = 99
(7 + 2w)*w = 99
by solving we find
w = 5.5 yd
click here to see the step solution of the equation
l = 7 + 2*5.5
l = 18
the dimensions of the rectangle are: the length is 18 yd and the width is 5.5 yd.