Problema Solution
The area of a rectangle is 14 ft^2 , and the length of the rectangle is 3 ft less than twice the width. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the area of a rectangle is 14 ft^2
l*w = 14
the length of the rectangle is 3 ft less than twice the width
l = 2w - 3
plug l = 2w - 3 into l*w = 14
(2w - 3)*w = 14
by solving we find
w = 3.5 ft
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l = 2*3.5 - 2
l = 5 ft
the dimensions of the rectangle are: the width is 3.5 ft and the length is 5 ft.