Problema Solution
Part of the proceeds form a garage sale was $280 worth of $5 and $10 bills. If there were 20 more $5 bills than $10 bills. Find the number of each
Answer provided by our tutors
let
x = the number of $5 bills
y = the number of $10 bills
there were 20 more $5 bills than $10 bills
x = y + 20
the garage sale was $280 worth
5x + 10y = 280 divide both sides by 5
x + 2y = 56
by solving the system of equations
x = y + 20
x + 2y = 56
we find
x = 32 bills of $5
y = 12 bills of $10
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there are 32 bills of $5 and 12 bills of $10.