Problema Solution
The area of a rectangle is 35 yd^2, and the length of the rectangle is 8 yd less than 3 times the width. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the area of a rectangle is 35 yd^2
l*w = 35
the length of the rectangle is 8 yd less than 3 times the width
l = 3w - 8
plug l = 3w - 8 into l*w = 35
(3w - 8)*w = 35
by solving we find
w = 5 yd
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l = 3*5 - 8
l = 7 yd
the dimensions of the rectangle are: the width is 5 yd and the length is 7 yd.