Problema Solution

Two times the square root of the sum of 3 consecutive even numbers is 24. Find the three numbers.

Answer provided by our tutors

let the 3 consecutive even numbers be:


2x - 2, 2x and 2x + 2, where x is integer


2 times the square root of the sum of 3 consecutive even numbers is 24:


2(√(2x - 2 + 2x + 2x + 2)) = 24


2√(6x) = 24 divide both sides by 2


√(6x) = 12


6x = 12^2


x = 144/6


x = 24


the 3 consecutive even numbers are:


2*24 - 2 = 46


2*24 = 48


2*24 + 2 = 50.