Problema Solution
Two times the square root of the sum of 3 consecutive even numbers is 24. Find the three numbers.
Answer provided by our tutors
let the 3 consecutive even numbers be:
2x - 2, 2x and 2x + 2, where x is integer
2 times the square root of the sum of 3 consecutive even numbers is 24:
2(√(2x - 2 + 2x + 2x + 2)) = 24
2√(6x) = 24 divide both sides by 2
√(6x) = 12
6x = 12^2
x = 144/6
x = 24
the 3 consecutive even numbers are:
2*24 - 2 = 46
2*24 = 48
2*24 + 2 = 50.