Problema Solution

The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44ft^2 . Find the dimensions of the rectangle.

Answer provided by our tutors

let


l = the length of the rectangle, l>0

w = the width of the rectangle, w>0


The length of a rectangle is 3 ft less than double the width


l = 2w - 3


the area of the rectangle is 44ft^2


l*w = 44


plug l = 2w - 3 into l*w = 44


(2w - 3)*w = 44


by solving we find


w = 5.5 ft


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l = 2*5.5 - 3


l = 8 ft


the length of the rectangle is 8 ft, while the width is 5.5 ft.