Problema Solution
The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?
Answer provided by our tutors
the 3 consecutive positive integers can be written as:
x - 1, x and x, where x is positive integer
the sum of the squares of 3 consecutive positive integers is 116
(x - 1)^2 + x^2 + (x + 1)^2 = 116
by solving we find
x = 6.16
click here to see the step by step solution of the quadratic equation
the solution is not an integer thus the problem has no solutions (there are no such 3 consecutive integers).