Problema Solution
The perimeter of a rectangle is 19 ft. The areas is 15 sq. feet. What are the dimensions of the rectangle?
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let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
The perimeter of a rectangle is 19 ft
2(l + w) = 19 divide both sides by 2
l + w = 9.5
l = 9.5 - w
The areas is 15 sq. feet
l*w = 15
plug l = 9.5 - w into the last equation:
(9.5 - w)*w = 15
by solving we find
w1 = 2 ft
w2 = 7.5
click here to see the step by step solution of the equation
l = 9.5 - 2
l = 7.5 ft
one solution for the dimensions is: the length is 7.5 feet and the width is 2 feet.
for w = 7.5 we find l = 9.5 - 7.5 = 2 ft but we also assume that the length is bigger then the width and in this case this condition is not satisfied.