Problema Solution
Andrew can paint the neighbor's house 6 times as fast as bailey. The year Andrew and bailey worked together, it took them 5 days. How long would it take each to paint the house?
Answer provided by our tutors
let
a = the number of days Andrew needs to paint the house alone thus the rate of Andrew is 1/a house per day
b = the number of days Bailey needs to pain the house alone thus the rate of Bailey is 1/b house per day
Andrew can paint the neighbor's house 6 times as fast as Bailey
a = b/6
The year Andrew and bailey worked together, it took them 5 days:
1/a + 1/b = 1/5
plug a = b/6 into the last equation
1/(b/6) + 1/b = 1/5
by solving we find
b = 35 days
click here to see the step by step solution of the equation
a = 35/6
a = 5 5/6 days
a = 5 days (5/6)*24 hours
a = 5 days 20 hours
Andrew will paint the house alone in 5 days 20 hours.
Bailey will paint the house alone in 35 days.