Problema Solution
The length of a rectangle is 6 feet longer than its width. The perimeter is 48 feet. Write a mathematical expression for the width of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
P = 48 ft the perimeter of the rectangle
The length of a rectangle is 6 feet longer than its width:
l = 6 + w
The perimeter of the rectangle is P = 2(l + w) thus
2(l + w) = 48 divide both sides by 2
l + w = 24
plug l = 6 + w into l + w = 24
(6 + w) + w = 24
2w + 6 = 24
w = (1/2)(24 - 6)
w = 9 ft
the width of the rectangle is 9 ft.