Problema Solution
Two buses leave a station at the same time and travel in opposite directions. One bus travels 20km/h slower than the other. If the two buses are 1750 km apart after 7 hours, what is the rate of each bus?
Answer provided by our tutors
let
v = the rate of slower bus
v + 20 = the rate of the faster bus
t = 7 hours
since distance = rate*time and the travel in opposite direction we have:
v*t + (v + 20)*t = 1750
7v + (v + 20)*7 = 1750
by solving we find
v = 115 km/h
click here to see the step by step solution of the equation
v + 20 = 115 + 20 = 135 km/h
the rate of the faster bus is 135 km/h.
the rate of the slower bus is 115 km/h.