Problema Solution
A youth organization collected nickels and dimes for charity drive. By the end of the 1 day drive, the youth had collected $68.75. If there were five times as many dimes as nickels, how many of each type of coin was collected?
The number of nickels was?
The number of dimes was?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
let
n = the number of nickels, n>0, n is integer
d = the number of dimes, d>0, d is integer
By the end of the 1 day drive, the youth had collected $68.75 = 6875 cents:
5n + 10d = 6875 divide both sides by 5
n + 2d = 1375
there were five times as many dimes as nickels:
d = 5n
plug d = 5n into n + 2d = 1375
n + 2(5n) = 1375
by solving we find
n = 125 nickles
click here to see the step by step solution of the equation:
d = 5*125
d = 625 dimes
the number of nickles was 125.
the number of dimes was 625.