Problema Solution
How many mL of a 48% acid solution must be added to 24 mL of a 12% acid solution to produce a 30% acid solution?
Answer provided by our tutors
let
x = mL of the 48% acid solution
0.48*x + 0.12*24 = 0.30(x + 24)
by solving we find
x = 24 mL
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24 mL of 48% acid solution must be added.