Problema Solution
the area of a rectangular field is 162 square meters and its length is twice its width find the dimension of the field
Answer provided by our tutors
let
l = the length of the field, l>0
w = the width of the field, w>0
A = 162 m^2 the area of the field
since A = l*w we have
l*w = 162
its length is twice its width
l = 2w
plug l = 2w into l*w = 162
2w*w = 162
by solving we find
w = 9 m
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l = 2*9
l = 18 m
the dimensions of the field are: the length is 18 meters and the width is 9 meters.