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## Problema Solution

Marcus invested s sum of money at 5%. He invested an amount of money \$250 more than the first amount at 6%. If the annual income from both investments totaled \$59, how much did he invest at each rate. Use table and the 5-step method to solve this problem.

## Answer provided by our tutors

Let x represent the first amount invested at 5%

Therefore, (x+ \$250) would be the amount invested at 6%

question States***

.05x + .06(x + \$250) = \$59

solving for x

.05x + .06x + .06*\$250 = %59

.11x = \$59 - .06*\$250

.11x = \$59 - \$15

.11x = \$44

x = \$44/.11 = \$400, amount invested at 5%

the amount invested at 6% would be \$650 (\$400+ \$250)

.05*\$400 + .06*\$650 = \$20 + \$39 = \$59

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