Problema Solution
A diesel train made a trip to the repair yards and back. The trip there took 15 hours and the trip back took 18 hours. What was the diesel train's average speed on the trip there is it averaged 35 km/h on the return trip?
Answer provided by our tutors
let
v1 = the average speed of the trip there
v2 = 35 km/h the average speed of the return tirp
t1 = 15 hr the time of the trip there
t2 = 18 hr the time of the return trip
d = the distance traveled in one direction
since the average speed = distance/time we have
v2 = d/t2
d = v2*t2
d = 35*18
d = 630 km
the average speed of the trip there is
v1 = d/t1
v1 = 630/15
v1 = 42 km/h
the diesel train's average speed on the trip there is 42 km/h.