Problema Solution
How many liters of a 50% acid solution must be mixed with a 10% acid solution to get 240L of a 40% acid solution.
Answer provided by our tutors
let
x = liters of 50% acid solution
y = liters of 10% acid solution
x + y = 240
0.50x + 0.10y = 0.40*240
by solving the above system of equations we find
x = 180 liters
y = 60 liters
click here to see the step by step solution of the system of equations
180 liters of 50% acid solution should be mixed with 60 liters of 10% acid solution.