Problema Solution
a jet flew at an average speed of 480 mph from point X to point y. Because of head winds, the jet averaged only 440 mph on the return trip, and the return trip took 15 minutes longer. How many hours was the flight from Point y to point x? How far is it from point x to point y?
Answer provided by our tutors
we will assume that the plane had tailwind flying from X to Y
let
v = the speed of the plane in still air
w = the speed of the wind
traveling with tailwind the speed of the plane is: v + w = 480
traveling with head with the speed of the plane is: v - w = 440
t = the time of the trip from X to Y
t + 15/60 = t + 1/4 hr is the time of the return trip from Y to X
since distance = speed*time we have
(v + w)t = (v - t)(t + 1/4)
480t = 440(t + 1/4)
by solving we find
t = 2.75 hr
t = 2 hr 45 min
click here to see the step by step solution of the equation
2 hr 45 min + 15 min = 3 hr was the flight from Y to X.
distance = 480*2.75
distance = 1320 mi is the distance from X to Y.