Problema Solution
Find the dimensions of a rectangular enclosure with perimeter 52 yd and area 120 yd2.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
w < l
the perimeter is 52 yd means
2(l + w) = 52 divide both sides by 2
l + w = 26
l = 26 - w
the area is 120 yd means
l*w = 120 plug l = 26 - w into the last equation
(26 - w)*w = 120
by solving we find
w = 6 yd
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l = 26 - 6
l = 20 yd
the length of the rectangular enclosure is 20 yards.
the width of the rectangular enclosure is 6 yards.