Problema Solution
a jet travels 3020 miles against the wind in 5 hours and 3820 miles with the wind in the same amount of time. what is the rate of the jet in still air and what is the rate of the wind?
Answer provided by our tutors
let
j = the rate of the jet in still air
w = the rate of the wind
d1 = 3,020 mi the distance traveled against the wind
d2 = 3,820 mi the distance traveled with the wind
the speed of the jet traveling with the wind is: j + w
the speed of the jet traveling against the wind is: j - w
since speed = distance/time => time = distance/speed we have
3010/(j - w) = 5
5(j - w) = 3010 divide both sides by 5
j - w = 602
3820/(j + w) = 5
5(j + w) = 3820 divide both sides by 5
j + w = 764
by solving the system of equations
j - w = 602
j + w = 764
we find
j = 683 mph
w = 81 mph
click here to see the step by step solution of the system of equations
the rate of the jet in still air is 683 mph.
the rate of the wind is 81 mph.