Problema Solution
Five years ago, a mother was twice as old as her son. In 6 years time, the sum of their ages will be 82. Find their present ages.
Answer provided by our tutors
let
m = the present age of the mother
s = the present age of the son
Five years ago, a mother was twice as old as her son
m - 5 = 2(s - 5)
In 6 years time, the sum of their ages will be 82
m + 6 + s + 6 = 82
m + s + 12 = 82
m + s = 70
by solving the system of equations
m - 5 = 2(s - 5)
m + s = 70
we find
m = 45 years
s = 25 years
click here to see the step by step solution of the system of equations
the mother is 45 years old now.
the son is 25 years old now.