Problema Solution
How many liters of a 15% solution and a 33% solution is needed to have 120 liters of 21% solution?
Answer provided by our tutors
let
x = liters of the 15% solution
y = liters of the 33% solution
x + y = 120
0.15x + 0.33y = 0.21*120
by solving the above system of equations we find
x = 80 liters
y = 40 liters
click here to see the step by step solution of the system of equations
80 liters of the 15% solution should be mixed with 40 liters of the 33% solution.