Problema Solution
A jet travels 5985 mi against the wind in 9 hours and 6975 mi with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?
Answer provided by our tutors
let
j = the rate of the jet in still air
w = the rate of the wind
d1 = 5,985 mi the distance traveled against the wind
d2 = 6,975 mi the distance traveled with the wind
t = 9 hr the time of the travel in one direction
the speed of the jet traveling against the wind is: j - w
the speed of the jet traveling with the wind is: j + w
since speed = distance/time we have
traveling against the wind
j - w = d1/t
j - w = 5985/9
traveling with the wind
j + w = d2/t
j + w = 6975/9
by solving the system of equations
j - w = 5985/9
j + w = 6975/9
we find
j = 720 mph
w = 55 mph
click here to see the step by step solution of the system of equations
the rate of the jet in still air is 720 mph.
the rate of the wind is 55 mph.