Problema Solution
assume you are throwing a baseball up from the top of a building. The equation for the height of the ball, h, at time, t, is represented by the equation: h=-16t^2+64t+512 After how many seconds does the ball reach 560 ft?
Answer provided by our tutors
h(t)=-16t^2+64t+512
we need to find t such that h(t) = 560 ft
-16t^2+64t+512 = 560
by solving we find
t1 = 1 s
t2 = 3 s
click here to see the step by step solution of the equation:
the ball is 560 ft high: once after the first second and second time after the third second.