Problema Solution
Train A and B are traveling in the same direction on parallel tracks, train age traveling at 80 mi./h and train be is traveling at 88 mi./h, train A passes the station at 6:20 PM train the past is the same station at 6:50 PM at what time will train b catch up to train a?
Answer provided by our tutors
Consider at time 2:20,
Train B arrives at stn, but train A is 10mins ahead = 40x10/60 = 6.66 miles ahead.
say it takes time t for train B to catch up with A
60t = 6.66 + 40t
t = 6.66/20 = 0.333 hrs = 20mins
so time when train B passes train A = 2:20+ 20 mins = 2:40