Problema Solution
Calvin has six times as many dimes add quarters. He has a total of 21 coins that have a total value of $2.55. How much dimes and quarters does he have.
Answer provided by our tutors
1 dime = 10 cents
1 quarter = 25 cents
let
d = the number of dimes, d>0, d is integer
q = the number of quarters, q>0, q is integer
Calvin has six times as many dimes as quarters
d = 6q
He has a total of 21 coins that have a total value of $2.55 = 255 cents
d + q = 21
10d + 25q = 255
by solving the above system of equations we find
d = 18 dimes
q = 3 quarters
click here to see the step by step solution of the system of equatuons
indeed 18 = 6*3
Calvin has 18 dimes and 3 quarters.