Problema Solution
the oerimiter of tinas rectangular garden is 60 feet. If the langth of the garden is twice the width, what are the dementions of the garden
Answer provided by our tutors
let
l = the length of the garden
w = the width of the garden
the perimeter of Tina's garden is 60 feet
2(l + w) = 60 divide both sides by 2
l + w = 30
the length of the garden is twice the width
l = 2w
by solving the system of equations
l + w = 30
l = 2w
we find
l = 20 ft
w = 10 ft
click here to see the step by step solution of the system of equations
the dimensions of the garden are: the length is 20 ft and the width is 10 ft.