Problema Solution
The length of a rectangle is 6ft longer than its width . If the perimeter of the rectangle is 52 find its area
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
The length of a rectangle is 6 ft longer than its width
l = 6 + w
the perimeter of the rectangle is 52
2(l + w) = 52 divide both sides by 2
l + w = 26
by solving the system of equations:
l = 6 + w
l + w = 26
we find
l = 16 ft
w = 10 ft
click here to see the step by step solution of the system of equations:
the area A = width*length or
A = l*w
A = 16*10
A = 160 ft^2
the area of the rectangle is 160 ft^2.