Problema Solution

In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home runs. How many home runs did each player hit?

Answer provided by our tutors

let


p = the number of home runs that Peter hit


a = the number of runs that Alice hit


Peter hit twice the difference of the number of home runs Alice hit and 6:


p = 2(a - 6)


Altogether, they hit 18 home runs:


p + a = 18


by solving the system of equations:


p = 2(a - 6)


p + a = 18


we find


a = 10 home runs


p = 8 home runs


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Peter hit 8 home runs.


Alice hit 10 home runs.