Problema Solution
the sum of three odd consecutive integers is less than 100. find the largest of these integers.
Answer provided by our tutors
let 2n+1 represent the first odd integer, then '2n+3' and '2n+5' represent the next two odd integers
(2n+1)+(2n+3)+(2n+5) < 100
solving for 'n' we have:
n < 15.1
let n=15, then 2*15+5 = 35
the largest possible number is 35