5. Find the base angles of an isosceles triangle if the vertex angle is :

a.48 degrees

b. 70 degrees 41 minutes

c. 102 degrees 37 minutes

d. 30 degrees 42 minutes

e.56 degrees 38 minutes 46 seconds

f. 100 degrees 24.8 minutes

Solution:

The base angle = (180 degrees - vertex angle)/2

(a)The base angle = (180 degrees - 48 degrees)/2 = 66 degrees

(b)The base angle = (180 degrees - 70 degrees 41 minutes)/2 = 54 degrees 39 minutes 30 seconds

(c)The base angle = (180 degrees - 102 degrees 37 minutes)/2 = 38 degrees 41 minutes 30 seconds

(d)The base angle = (180 degrees - 30 degrees 42 minutes)/2 = 74 degrees 39 minutes

(e)The base angle = (180 degrees - 56 degrees 38 minutes 46 seconds)/2 = 61 degrees 40 minutes 37 seconds

(f)The base angle = (180 degrees - 100 degrees 24.8 minutes)/2 = 39 degrees 47.6 minutes