Problema Solution
the perimeter of a rectangle is 500yards. what are the dimensions of the rectangle if the length is 60yards more then the width.
Answer provided by our tutors
let
w = the width of the rectangle
l = the length of the rectangle
the perimeter of a rectangle is 500 yards:
2(l + w) = 500 divide both sides by 2
l + w = 250
the length is 60 yards more then the width:
l = 60 + w
by solving the system of equations:
l + w = 250
l = 60 + w
we find:
l = 155 yd
w = 95 yd
click here to see the step by step solution of the system of equations:
the length of the rectangle is 1500 yards.
the width of the rectangle is 95 yards.