Problema Solution
how many gallons of a 70% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 60% antifreeze?
Answer provided by our tutors
let
x = the gallons of 70% antifreeze solution
0.70x + 0.10*100 = 0.60(x + 100)
by solving we find:
x = 500 gal
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500 gallons of 70% antifreeze solution should be used for the mix.